pa help po grade 11 stem pre calculus
1. pa help po grade 11 stem pre calculus
Answer:
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2. pa help po grade 11 stem pre calculus please
Grade 11
Answer:
b
d
b
a
c
b
d
c
a
c
Step-by-step explanation:
Hope it Helpes!
3. pa help po grade 11 stem pre calculusasap
Answer:
1. c
2. a
3. c
4.
5. d
Step-by-step explanation:
Hindi ko po alam number 4 medyo mahirap
4. mga konseptong pangwika grade 11 pdf
Ang konsepto ng wika ay bilang isang kasangkapan sa komunikasyon na nagsisilbing maghatid ng mga mensahe sa iba.
Paliwanag:
Ang wika ay isang paraan ng komunikasyon at ang komunikasyon ay ang proseso ng paglilipat ng mga mensahe
Ang mga wika ay dynamic na nagbabago sa pamamagitan ng pagsunod sa mga arrow. nakikita kapag ang mga tao ay naging mas mahusay sa paggamit ng verbal at nonverbal na wika kapag nagpapalitan ng awa, nagpapakita ng pag-unawa sa sinasabi ng awa, at pag-ungol ng hindi berbal na pag-uugali.
Ang wika ay likas na dinamiko, ibig sabihin ay hindi ito maihihiwalay sa posibilidad ng mga pagbabagong nagaganap sa paglipas ng panahon. Ang wika ay umuunlad kasunod ng pag-unlad ng kultura at mga palaso, kung saan ang dalawang bagay na ito ay tiyak na hindi titigil at ganoon na lamang, bagkus ay patuloy na lalago.
Ang wika ay anumang anyo ng komunikasyon kung saan ang mga kaisipan at damdamin ng tao ay sinasagisag upang ihatid ang kahulugan ng iba. Ang wika ay isang kasangkapan sa komunikasyon para sa pakikipagkaibigan, at pag-aaral ng maraming bagay sa kanilang paligid. Sa pamamagitan ng komunikasyon, nagkakaroon ang mga bata ng pag-unawa sa bagong kaalaman tungkol sa iba pang mga bagay.
Ang wika ay may mahalagang papel sa pag-unlad ng bata. Maaaring mapadali ng wika ang interpersonal at komunikasyon, tumulong sa pagsasaayos ng mga kaisipan, at makakatulong sa pag-aaral ng mga bagay. Ang pagpapaunlad ng mga kasanayan sa komunikasyon ay mahalaga sa konteksto ng pag-aaral ng wika.
Karaniwang ang wika ay isang sistema, ibig sabihin, ang wika ay nabuo sa pamamagitan ng mga salita na may nakapirming pattern at may mga patnubay dito. Sa pahayag na ang wika ay isang sistema na may tiyak na pattern, malinaw na sa isang wika ay magkakaroon ng mga subsystem. Kasama sa subsystem na ito ang ponolohiya, morpolohiya, at syntax.
Huwag isipin na ang wika ay:
Ang ponolohiya ay naglalarawan ng sound system sa wika. Ang mga ponema ay mga yunit ng tunog na bumubuo sa mga salita.
Pinag-aaralan ng semantika ang kahulugan ng mga salita at pangungusap.
Inilalarawan ng gramatika ang istruktura ng wika, syntax (isang set ng mga tuntunin sa gramatika na nagtuturo kung paano bumuo ng mga salita sa mga pangungusap), morphemes (ang pinakamaliit na predictable na yunit ng wika).
Ang pragmatics ay binubuo ng patnubay kung paano magsalita ng tamang wika sa kontekstong panlipunan (ang mga bagay na ginagamit natin sa simpleng wika kapag nakikipag-usap sa mga bata).
Karaniwan, ang wika ay ginagamit bilang isang paraan ng pagpapahayag ng sarili, isang paraan ng komunikasyon, isang paraan ng panlipunang pagbagay sa kapaligiran at sitwasyon nito, at panlipunang kontrol. Ang wika ay isang koleksyon din ng mga salita kung saan ang bawat salita ay may abstract na kahulugan at nauugnay sa isang konsepto.
Mayroong dalawang dahilan kung bakit ang wika ay isang mahalagang kasangkapan sa komunikasyon, ito ay ang wika ay ginagamit ng mga tao upang ihatid ang mga kaisipan, damdamin, ideya, iba pa. Ang wika ay isang paraan ng pagbalangkas ng mga intensyon, pagpukaw ng damdamin, paglikha ng pagtutulungan.
Higit pa tungkol sa konsepto ng Wika
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5. basic calculus pang grade 11 po thanks
Ang Labo po ng pic Kasing labo ng mata ko Hihi Sorry
6. Solve the given problem Is there any significant relationship between the grades of selected STEM students in Pre - Calculus and Basic Calculus? At alpha 0.05 (Data as follows) Pre- Calculus (x) 80 75 78 88 83 84 91 82 86 90 81 83 Basic Calculus (y) 90 81 84 90 80 79 91 83 80 93 84 87 No. xy 1 2 3 4 5 6 7 8 9 10 11 12 Total
Thank YouForPoints
pasensya napo wala po kasi yung para pomakapag solve.
7. answer key pre calculus 11
Answer:
ano po yan brainleyest po please
8. Pahelp po grade 11 stem
Why are plant cells have more in common with the bacterial cells than the animal cell?
'Cause both plant and bacterial cell have a large vacuole that contains a large amount of water.9. Stem- pre calculusFind the center/radius and convert to the general form (x-3)² + (Y-3)² =4
Answer:
A.4
B.8
C.9
D.1
Step-by-step explanation:
ANSWER: A.
10. please answer this grade 11 stem.?
Answer:
1.D
2.C
3.D
4.B
5.A
6.A
7.A
8.A
9.B
10.D
ang pagod ha
sana makatulong
11. komunikasyon grade 11 module pdf
Answer:
where's the question po
Step-by-step explanation:
ssorry I didn't understand you
walang tanong ehh sorry follow nalang kita tapos ako rin
12. help :') basic calculus trigo derivative grade 11
Answer:
Sure! Here's a basic calculus problem involving trigonometric functions and their derivatives:
Find the derivative of the function f(x) = sin(x) + cos(x) at x = pi/4.
Solution:
To find the derivative of f(x), we need to find the derivative of each term separately and then add them together:
f(x) = sin(x) + cos(x)
f'(x) = d/dx (sin(x)) + d/dx (cos(x))
Using the chain rule, we get:
f'(x) = cos(x) - sin(x)
Now we can evaluate f'(x) at x = pi/4:
f'(pi/4) = cos(pi/4) - sin(pi/4)
Using the values of cosine and sine at pi/4 (which are both equal to sqrt(2)/2), we get:
f'(pi/4) = sqrt(2)/2 - sqrt(2)/2
Simplifying, we get:
f'(pi/4) = 0
13. Solutions to problems in differential and integral calculus ricardo asin pdf
Answer:
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14. need help po asap grade 11 pre calculus
pa picture po ng maayos di ko po mabasa sorry po
15. pang grade 11 po siya basic calculus salamat po
Answer:
-13
12
Step-by-step explanation:
sana po makatulong
16. sino po ba May answer key sa pre calculus STEM grade 11 nahihirapan na po ako module 2-5
Answer:
WALA PO AKO SORRY PO (｡•́︿•̀｡)
17. komunikasyon grade 11 module pdf answer key
Answer:
grade 6 palang po ako
meron po ba kayo grade 6
math hirap po eh
Explanation:
pa brainly po
18. PLEASE HELP ME I'm a Grade 11, This math subject is basic calculus.
1. y' = -3/(x-4)^2
2. y^ prime = 6x + 10
3. y' = (4x^3 + 2x^2 + (2x - 1) * -2) / (2x-1)^2
4. y'-12x^-5+ (5/2x^0.5)
5. y^ prime = (30x ^ 2 + 30x)(6 + 3x ^ 2) + (5x - 1)(2x)
6. y^ prime = e ^ x * (1 + x)
7. y^ prime =3x^ ^ 2^ * cos(x)-x^ ^ 3^ * - sin(x)
8. y^ prime =2x^ * ln(x) + x ^ 2 / x = 2x * ln(x) + x
19. pre calculus 11 answer
Answer:
needed on of the questions
20. poor performan in Grade 11 stem
anong instructions
Step-by-step explanation:
tsaka performance po yan
Answer:
performance po yan
Step-by-step explanation:
kayo po dapat gumawa nyan o ivideo yan po
21. why calculus is connected to stem
Answer:
Calculus is a service course for almost all science, technology, engineering, and mathematics (STEM) degrees, and thus must support the content needs of those fields.
Answer:
Calculus is a service course for almost all science, technology, engineering, and mathematics (STEM) degrees, and thus must support the content needs of those fields.
Explanation:
22. Pre - calculus Grade 11
Answer:
Sorry don't now it I'm gana try
23. how does calculus help stem students
Answer:
Calculus is often thought of as the college mathematics course, with the main goal of mathematically preparing students for degrees in STEM, but it is also often seen as beneficial to students in non-STEM degree programs for developing critical thinking and problem solving experience.
24. why Pre-Calculus is important for non stem students
Answer:
Precalculus is especially important because it provides you with the building blocks that you will need to learn in the higher up courses. If you are not able to keep up with the lessons that are being taught in your precalculus course, you may run the risk of falling behind the rest of the class.
Step-by-step explanation:
#carry on learning
Answer:Precalculus is especially important because it provides you with the building blocks that you will need to learn in the higher up courses. If you are not able to keep up with the lessons that are being taught in your precalculus course, you may run the risk of falling behind the rest of the class
Step-by-step explanation:
25. Pahelp po guys Las 3 Pre calculus grade 11
Step-by-step explanation:
ang hirap Hindi ko masagotan
26. need ko na po sya ngayon pang grade 11 na po yan pre calculus hirap po kasi lahat po yan sasagutan
Answer:
1. Find the general equation of a Parabola with Vertex at (2,1) and directrix at x=5.
Since the directrix is a vertical line, the parabola opens horizontally. The focus is located at a distance of a = 3 units to the left of the vertex.
The general equation of a parabola with vertex (h,k), focus (h-a,k), and directrix x = h+a is:
(x - h)^2 = 4a(y - k)
Substituting the given values, we have:
(x - 2)^2 = 12(y - 1)
This is the general form of the parabolic equation. To sketch the graph, we can plot the vertex (2,1) and the point on the directrix that is closest to the vertex, which is (5,1). The focus is located 3 units to the left of the vertex, so it is at (-1,1). We can also plot a few more points on the parabola by substituting values of x and solving for y. The resulting graph should be a horizontal parabola opening to the left.
2. Find the general equation of a Parabola with Focus at (-1, -6) and directrix at y=0.
Since the directrix is a horizontal line, the parabola opens vertically. The vertex is located at the midpoint between the focus and the directrix, which is (−1,−3).
The general equation of a parabola with vertex (h,k), focus (h,k+a), and directrix y = k-a is:
(y - k)^2 = 4a(x - h)
Substituting the given values, we have:
(y + 3)^2 = 24(x + 1)
This is the general form of the parabolic equation. To sketch the graph, we can plot the vertex (−1,−3) and the focus (−1,−6). We can also plot a few more points on the parabola by substituting values of y and solving for x. The resulting graph should be a vertical parabola opening downward.
3. Find the general equation of a Parabola with Vertex at (2,3) and with the end points of Latus Rectum are (6,1) & (-2,1).
The Latus Rectum (LR) is a line segment that passes through the focus and is perpendicular to the axis of symmetry. The length of the LR is equal to 4a, where a is the distance between the vertex and the focus. Since the LR passes through (6,1) and (−2,1), its length is 8 units. Thus, a = 2 units.
The vertex is located at (2,3), which is the midpoint of the LR. Therefore, the focus is located at a distance of 2 units above and below the midpoint, which are (2,5) and (2,1), respectively.
The general equation of a parabola with vertex (h,k), focus (h,k+a), and directrix y = k-a is:
(y - k)^2 = 4a(x - h)
Substituting the given values, we have:
(y - 3)^2 = 16(x - 2)
This is the general form of the parabolic equation. To sketch the graph, we can plot the vertex (2,3) and the focus (2,5) and (2,1). We can also plot the LR by connecting the endpoints (6,1) and (−2,1). The resulting graph should be a vertical parabola opening upward.
4. To find the equation of a parabola with left and right (LR) points, we use the standard form:
(x-h)² = 4a(y-k) where (h, k) is the vertex of the parabola.
From the given LR points (-2, 4) and (6, 4), we can see that the vertex lies on the line y=4, since the LR points are equidistant from the vertex. Also, since the parabola is opening upward, the value of 'a' must be positive.
Therefore, the vertex is at (h, k) = (2, 4) and a = 1/4a.
Substituting these values in the standard form, we get:
(x-2)² = 4(1/4)(y-4)
(x-2)² = (y-4)
x² - 4x + 4 = y
y = x² - 4x + 4
To sketch the graph, we can plot the vertex at (2, 4) and use the LR points to determine the shape of the parabola. Since the LR points are equidistant from the vertex, the parabola must be symmetrical about the line x=2.
The parts of the parabola are:
Vertex: (2, 4)
Vertex: (2, 4)Axis of symmetry: x = 2
Vertex: (2, 4)Axis of symmetry: x = 2Focus: (2, 15/4)
Vertex: (2, 4)Axis of symmetry: x = 2Focus: (2, 15/4)Directrix: y = 11/4
5. Now, let's find the general equation of a parabola with vertex at (-4, -3), a vertical x-axis, and passing through point (0, -1).
Since the vertex is at (-4, -3), the standard form will be:
(x+4)² = 4a(y+3)
Since the parabola has a vertical axis, we have to use the form (x-h)² = 4a(y-k).
Now, we need to find the value of 'a' to complete the equation. To do this, we use the point (0, -1) that the parabola passes through:
(0+4)² = 4a(-1+3)
16 = 8a
a = 2
Substituting this value of 'a' in the standard form, we get:
(x+4)² = 8(y+3)
Expanding the left-hand side, we get:
x² + 8x + 16 = 8(y+3)
x² + 8x + 16 = 8y + 24
8y = x² + 8x - 8
Dividing both sides by 8, we get the general equation of the parabola:
y = (1/8)x² + x - 1
The parts of the parabola are:
Vertex: (-4, -3)
Vertex: (-4, -3)Axis of symmetry: x = -4
Vertex: (-4, -3)Axis of symmetry: x = -4Focus: (-4, -19/8)
Vertex: (-4, -3)Axis of symmetry: x = -4Focus: (-4, -19/8)Directrix: y = -5/8
27. The final exam of grade 11 stem in pre-calculus has a mean of 85 and a standard deviation of 4. find the corresponding z-score for each of the following raw score a.82 b.76 c.93
Answer:
c93 sure po ako
Step-by-step explanation:
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28. Pre CalculusGrade 11Need Help
See picture analysis.
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29. What is the importance of calculus in stem
Answer:
the importance of Calculus is often thought of as the college mathematics course, with the main goal of mathematically preparing students for degrees in STEM, but it is also often seen as beneficial to students in non-STEM degree programs for developing critical thinking and problem solving experience.
30. What is pre calculus?
a course in mathematics that prepares a student for calculus.
Precalculus or preparatory calculus is a course with university or high school level algebra and trigonometry that is designed to prepare students for the study of calculus.
